a. 243 ⅕
b. (-8) ⅓
c. 125 -⅔
2. Nyatakan bilangan berikut dalam bentuk pecahan:
a. ⁵√64
b. ³√54
c. ⁴√ ¹/ 16³
3. Sederhanakan pernyataan dibawah ini dalam pangkat positif:
a. (3a² b-²)³ x (2a⁴)-²
b. P³/P Q/Q² R²/R³
c. (2x ²y)³
TOLONG
untuk soal nomor 2C seperti difoto brikut :
Penjelasan dengan langkah-langkah:
[tex]1. \: a. \: {243}^{ \frac{1}{5} } \\ = { ({3}^{5} )}^{ \frac{1}{5} } \\ = {3}^{5 \times \frac{1}{5} } \\ = 3 \\ b. \: { (- 8)}^{ \frac{1}{3} } \\ = { ({( - 2)}^{3}) }^{ \frac{1}{3} } \\ = {( - 2)}^{3 \times \frac{1}{3} } \\ = - 2 \\ c. \: {125}^{ - \frac{2}{3} } \\ = {( {5}^{3}) }^{ - \frac{2}{3} } \\ = {5}^{3 \times ( - \frac{2}{3}) } \\ = {5}^{ - 2} \\ = \frac{1}{ {5}^{2} } \\ = \frac{1}{25} [/tex]
[tex]2. \: a. \: \sqrt[5]{64} \\ = \sqrt[5]{ {2}^{6} } \\ = {2}^{ \frac{6}{5} } \\ b. \: \sqrt[3]{54} \\ = \sqrt[3]{ 27 \times 2 } \\ = \sqrt[3]{ {3}^{3} \times 2} \\ = 3 \sqrt[3]{2} \\ = 3. {2}^{ \frac{1}{3} } \\ c. \: \frac{1}{ \sqrt[4]{ {16}^{3} } } \\ = \frac{1}{ \sqrt[4]{ {( {2}^{4}) }^{3} } } \\ = \frac{1}{ \sqrt[4]{ {2}^{12} } } \\ = \frac{1}{ {2}^{ \frac{12}{4} } } \\ = \frac{1}{ {2}^{3} } \\ = \frac{1}{8} [/tex]
[tex]3. \: a. \: {(3 {a}^{2} {b}^{ - 2}) }^{3} \times {(2 {a}^{4}) }^{ - 2} \\ = {3 }^{3} {a}^{2 \times 3} {b}^{ - 2 \times 3} \times {2}^{ - 2} {a}^{4 \times ( - 2)} \\ = 27 {a}^{6} {b}^{ - 6} \times \frac{1}{ {2}^{2} } {a}^{ - 8} \\ = 27 {a}^{6 + ( - 8)} {b}^{ - 6} \times \frac{1}{4} \\ = 27 {a}^{ - 2} {b}^{ - 6} \times \frac{1}{4} \\ = \frac{27}{4 {a}^{2} {b}^{6} } \\ \\ b. \: \frac{ {p}^{3} }{p} \times \frac{q}{ {q}^{2} } \times \frac{ {r}^{2} }{ {r}^{3} } \\ = {p}^{3 - 1} {q}^{1 - 2} {r}^{2 - 3} \\ = {p}^{2} {q}^{ - 1} {r}^{ - 1} \\ = \frac{ {p}^{2} }{qr} \\ \\ c. \: {(2 {x}^{2}y) }^{3} \\ = {2}^{3} {x}^{2 \times 3} {y}^{3} \\ = 8 {x}^{6} {y}^{3} [/tex]
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